Increased efficacy of itoc int to char conversion

Was using a series of if statements.  This changes the operation so it just
adds 48 to the integer's given mod to get the ascii index of its corresponding
char.

1 files changed, 2 insertions, 21 deletions

diff --git a/src/common.c b/src/common.c
index 7cbdc3e..81f5641 100644
--- a/src/common.c
+++ b/src/common.c
@@ -64,27 +64,8 @@ int itoc(int num, char* out) {
   while(count >= 0) {
     int n = num%10;
 
-    if(n == 0) {
-      out[count] = '0';
-    } else if(n == 1) {
-      out[count] = '1';
-    } else if(n == 2) {
-      out[count] = '2';
-    } else if(n == 3) {
-      out[count] = '3';
-    } else if(n == 4) {
-      out[count] = '4';
-    } else if(n == 5) {
-      out[count] = '5';
-    } else if(n == 6) {
-      out[count] = '6';
-    } else if(n == 7) {
-      out[count] = '7';
-    } else if(n == 8) {
-      out[count] = '8';
-    } else if(n == 9) {
-      out[count] = '9';
-    }
+    // Add 48 to the int to get its char equivelant ascii index
+    out[count] = n + 48;
 
     num /= 10;
     count--;